Firstly, note that the highest common factor (HCF) of two or more numbers is also commonly called the greatest common divisor (GCD). Either way, it represents the highest/greatest number by which two (or more) other numbers can be divided.
It should be fairly obvious that the HCF of 4 and 6 is 2.
2 is the largest number that can divide both 4 and 6.
4 ÷ 2 = 2
6 ÷ 2 = 3
By observation, we can look at each equation in reverse to see that:
2×2 = 4
3×2 = 6
Have you spotted it?
2×2, or rather, 22, is the prime factorisation of 4;
3×2, or rather, 2×3, is the prime factorisation of 6.
2 is the highest number in both prime factorisations, which is why it is the HCF of 4 and 6.
The lowest common multiple (LCM, sometimes calles the least common multiple) of two or more numbers is the lowest/smallest number which is in the times table of the numbers.
Again, using 4 and 6, it should be fairly obvious that the LCM is 12.
12 is the smallest number which is in the 4 times table and the 6 times table.
One way this can be seen is to write out the times tables:
4 times table: 4 8 12
6 times table: 6 12
This can also be calculated using the Fundamental Theorem of Arithmetic.
We will take two numbers: 60 and 144
Find the prime factorisation of each one (in expanded form rather than index form):
60 = 2×2×3×5
144 = 2×2×2×2×3×3
Identify the numbers that appear in both lists: each list has two 2s and one 3.
60 = 2×2×3×5
144 = 2×2×2×2×3×3
Since each list contains 2×2×3, this means that:
HCF = 2×2×3 = 12
Since we have identified what is common to both lists of prime factors, the LCM must also include the numbers which are not common to both lists. In other words, we need 2×2×3 (which is common to both), but also 5×2×2×3 (which is not common to both, appearing in only one of the lists).
LCM = 2×2×3×5×2×2×3 = 720
Another way of looking at this is to just take one number and multiply it by the non-highlighted numbers in the list of the other number's prime factorisation:
LCM = 60×2×2×3 = 720
or
LCM = 144×5 = 720
Can you find the HCF and LCM of 20 and 30?
What about 56 and 84?
210 and 175?
It is also possible to use a very similar method to find the HCF and LCM of three (or more) numbers.
Can you find the HCF and LCM of 24, 84 and 150?
We will take two numbers: 60 and 144
Find the prime factorisation of each one (in expanded form rather than index form):
60 = 2×2×3×5
144 = 2×2×2×2×3×3
Identify the numbers that appear in both lists: each list has two 2s and one 3.
60 = 2×2×3×5
144 = 2×2×2×2×3×3
Since each list contains 2×2×3, this means that:
HCF = 2×2×3 = 12
Since we have identified what is common to both lists of prime factors, the LCM must also include the numbers which are not common to both lists. In other words, we need 2×2×3 (which is common to both), but also 5×2×2×3 (which is not common to both, appearing in only one of the lists).
LCM = 2×2×3×5×2×2×3 = 720
Another way of looking at this is to just take one number and multiply it by the non-highlighted numbers in the list of the other number's prime factorisation:
LCM = 60×2×2×3 = 720
or
LCM = 144×5 = 720
Can you find the HCF and LCM of 20 and 30?
What about 56 and 84?
210 and 175?
It is also possible to use a very similar method to find the HCF and LCM of three (or more) numbers.
Can you find the HCF and LCM of 24, 84 and 150?